博客
关于我
剑指offer--树--树中两个结点的最低公共祖先
阅读量:135 次
发布时间:2019-02-26

本文共 2510 字,大约阅读时间需要 8 分钟。

???????????????????????????????

  • ??????????????????????????????????????DFS???????
  • ??????????????????????????????????????????????
  • ??????????????

    import java.util.ArrayList;import java.util.Stack;public class Test2 {    public static void main(String[] args) {        // ????        TreeNode root = new TreeNode(6);        TreeNode left = new TreeNode(2);        left.left = new TreeNode(0);        left.right = new TreeNode(4);        left.right.left = new TreeNode(7);        left.right.right = new TreeNode(9);        root.left = left;        TreeNode right = new TreeNode(8);        right.left = new TreeNode(3);        right.left.right = new TreeNode(5);        root.right = right;        System.out.println(lowestCommonAncestorII(root, left, right));    }    public static TreeNode lowestCommonAncestorII(TreeNode root, TreeNode p, TreeNode q) {        List
    pPath = findPath(root, p); List
    qPath = findPath(root, q); // ??????????null if (pPath == null || qPath == null) { return null; } // ??????????????? int minLength = Math.min(pPath.size(), qPath.size()); TreeNode common = null; for (int i = 0; i < minLength; i++) { if (pPath.get(i) == qPath.get(i)) { common = pPath.get(i); } else { break; } } return common; } private static List
    findPath(TreeNode root, TreeNode target) { List
    path = new ArrayList<>(); Stack
    stack = new Stack<>(); stack.push(root); while (!stack.isEmpty()) { TreeNode node = stack.pop(); if (node == target) { // ????????????path? while (!stack.isEmpty()) { path.add(stack.pop()); } return path; } if (node.left != null) { stack.push(node.left); } if (node.right != null) { stack.push(node.right); } } return null; }}

    ????

  • findPath ???

    • ?????????????DFS?????????????????
    • ???????????????????????????????????
  • lowestCommonAncestorII ???

    • ?? findPath ??????????p?q????
    • ?????????????????????
    • ?????????????????????????????????????
  • ??????

    • main ???????????? lowestCommonAncestorII ???????????
    • lowestCommonAncestorII ?????????????????????????????
    • findPath ????????DFS?????????

    ????????????O(n)???????????????????????????????

    转载地址:http://tnzu.baihongyu.com/

    你可能感兴趣的文章
    Qt读取注册表默认值
    查看>>
    poj 1679 判断MST是不是唯一的 (次小生成树)
    查看>>
    POJ 1703 Find them, Catch them
    查看>>
    POJ 1703 Find them, Catch them 并查集
    查看>>
    POJ 1738 An old Stone Game(石子合并)
    查看>>
    POJ 1740 A New Stone Game(博弈)题解
    查看>>
    Qt网络编程之实例二POST方式
    查看>>
    POJ 1765 November Rain
    查看>>
    poj 1860 Currency Exchange
    查看>>
    POJ 1961 Period
    查看>>
    POJ 2019 Cornfields (二维RMQ)
    查看>>
    poj 2057 The Lost House 贪心思想在动态规划上的应用
    查看>>
    poj 2057 树形DP,数学期望
    查看>>
    poj 2112 最优挤奶方案
    查看>>
    Qt编写自定义控件12-进度仪表盘
    查看>>
    SpringBoot主启动原理在SpringApplication类《第六课》
    查看>>
    poj 2186 Popular Cows :求能被有多少点是能被所有点到达的点 tarjan O(E)
    查看>>
    POJ 2186:Popular Cows Tarjan模板题
    查看>>
    POJ 2229 Sumsets(递推,找规律)
    查看>>
    poj 2236
    查看>>